5x^2+45x-49860=0

Solution for 5x^2+45x-49860=0 equation:

5x^2+45x-49860=0

a = 5; b = 45; c = -49860;
Δ = b2-4ac
Δ = 452-4·5·(-49860)
Δ = 999225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{999225}=\sqrt{225*4441}=\sqrt{225}*\sqrt{4441}=15\sqrt{4441}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-15\sqrt{4441}}{2*5}=\frac{-45-15\sqrt{4441}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+15\sqrt{4441}}{2*5}=\frac{-45+15\sqrt{4441}}{10}
$